If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
x = 0
x^2 = 0
x = 0
x = 0
x^2 = 0
x^2 = 0
1*x^2 = 0 // : 1
x^2 = 0
x = 0
x in (-oo:0) U (0:+oo)
2-(9/(x^2)) = 5/x // - 5/x
2-(5/x)-(9/(x^2)) = 0
2-5*x^-1-9*x^-2 = 0
t_1 = x^-1
2-9*t_1^2-5*t_1^1 = 0
2-9*t_1^2-5*t_1 = 0
DELTA = (-5)^2-(-9*2*4)
DELTA = 97
DELTA > 0
t_1 = (97^(1/2)+5)/(-9*2) or t_1 = (5-97^(1/2))/(-9*2)
t_1 = (97^(1/2)+5)/(-18) or t_1 = (5-97^(1/2))/(-18)
t_1 = (97^(1/2)+5)/(-18)
x^-1-((97^(1/2)+5)/(-18)) = 0
1*x^-1 = (97^(1/2)+5)/(-18) // : 1
x^-1 = (97^(1/2)+5)/(-18)
-1 < 0
1/(x^1) = (97^(1/2)+5)/(-18) // * x^1
1 = ((97^(1/2)+5)/(-18))*x^1 // : (97^(1/2)+5)/(-18)
-18*(97^(1/2)+5)^-1 = x^1
x = -18*(97^(1/2)+5)^-1
t_1 = (5-97^(1/2))/(-18)
x^-1-((5-97^(1/2))/(-18)) = 0
1*x^-1 = (5-97^(1/2))/(-18) // : 1
x^-1 = (5-97^(1/2))/(-18)
-1 < 0
1/(x^1) = (5-97^(1/2))/(-18) // * x^1
1 = ((5-97^(1/2))/(-18))*x^1 // : (5-97^(1/2))/(-18)
-18*(5-97^(1/2))^-1 = x^1
x = -18*(5-97^(1/2))^-1
x in { -18*(97^(1/2)+5)^-1, -18*(5-97^(1/2))^-1 }
| 24+3-2X=35 | | 2x+25x=0 | | 4*x+12=24 | | 0.02+x=3.2 | | 14+2n-6+8n=4n-21+3n | | -5-n(1+7n)=-8 | | 4x-3y+5z=18 | | (2sinx-1)-(3cosx-1)=0 | | x^(1/x)=23 | | 5x*x=7x-1 | | 4/6*7 | | 2/6-3/10 | | 2x+2xyz= | | 16v^2-144=0 | | 15v^2-144=0 | | 14v^2-144=0 | | 13v^2-144=0 | | 18v^2-144=0 | | 3v^2-144=0 | | 4v^2-144=0 | | 5v^2-144=0 | | 6v^2-144=0 | | 7v^2-144=0 | | 8v^2-144=0 | | 9v^2-144=0 | | 13x^2-144=0 | | 24x^2-144=0 | | -8x+2y=1 | | 3(4x-1)=5(3+2x) | | 3x^3/2=81 | | 561x+966=1500623 | | (64n^12)-1/6 |